4x^2-35=1768

Solution for 4x^2-35=1768 equation:

4x^2-35=1768

We move all terms to the left:

4x^2-35-(1768)=0

We add all the numbers together, and all the variables

4x^2-1803=0

a = 4; b = 0; c = -1803;
Δ = b2-4ac
Δ = 02-4·4·(-1803)
Δ = 28848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28848}=\sqrt{16*1803}=\sqrt{16}*\sqrt{1803}=4\sqrt{1803}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{1803}}{2*4}=\frac{0-4\sqrt{1803}}{8}
=-\frac{4\sqrt{1803}}{8}
=-\frac{\sqrt{1803}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{1803}}{2*4}=\frac{0+4\sqrt{1803}}{8}
=\frac{4\sqrt{1803}}{8}
=\frac{\sqrt{1803}}{2}
$